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x^2+64x-1280=0
a = 1; b = 64; c = -1280;
Δ = b2-4ac
Δ = 642-4·1·(-1280)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-96}{2*1}=\frac{-160}{2} =-80 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+96}{2*1}=\frac{32}{2} =16 $
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